To find the first four items in an iterable (i.e., items 0, 1, 2, and 3), you only need a step size of 1 (which is the default). A step size of 2 (iterable[::2]) will give you only ever second item (which is not what you want), and a step size of -1 (iterable[::-1]) is going to go backward through the items, which is also not what you want.
Also, you're not stepping through a list of lists (if I recall correctly) so you don't need that second slice at all.
Since the first 4 items have a default start position as 0, you don't need to include it.
In my example below, it returns the first six items. See if you can figure out how to modify it to make it the first 4 items instead!
# The below is same as: return iterable[0:6:1] --> start at index 0,
# stop just before index 6, i.e., get items at index 0, 1, 2, 3, 4, and 5,
# and step size = 1, i.e., go forward 1 by 1.
# Start at 0 is the default so I can be lazy and leave that out.
# Step size of 1 is also the default so I be even more lazy
# and leave that out too.
Have another look at the video if you are still confused. Hope this helps.
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