Need help with a function that returns a list of tuples after unpacking two iterables.

Question

The task is to create a function that takes two iterables and then returns a list of tuples that follows the pattern: [(iterable1[0], iterable2[0]), (iterable1[1], iterable2[1]) ... ]. It keeps returning the error that there are to many items to unpack. Any help is greatly appreciated!

zippy.py

# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo(iterable1, iterable2):
    my_list = []
    for item, item_1 in iterable1, iterable2:
        my_list.append((item, item_1))
    return(my_list)

Answer 1 · 2016-08-03T19:21:41Z

August 3, 2016 7:21pm

You can't have two iterables in the same for loop.

But you could use the length of one as a range, and have an index you could apply to both.

Answer 2 · 2016-08-21T14:31:51Z

August 21, 2016 2:31pm

Why can't you have two iterables in the same for loop? Below is my code and I keep getting the message "Didn't get the right output. For example, expected (10, 'T') as the first item, got (10, 'T') instead.". This is very strange, because it appears to be getting the right answer, but for some reason it won't let me pass the code challange.

def combo(it1,it2):
    answer = []
    #i = len(it1)
    for item1 in it1:
        tup1 = item1
        for item2 in it2:
            tup2 = item2
            tup = (tup1,tup2)
            answer.append(tup)
    return answer

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Jonathan Shedd

Jonathan Shedd

Need help with a function that returns a list of tuples after unpacking two iterables.

2 Answers

Steven Parker

Steven Parker

You can't have two iterables in the same for loop.

Jonathan Shedd

Jonathan Shedd

Chris Jones

Chris Jones

Nathan Bivens

Nathan Bivens