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samuel fiori
4,497 PointsNEED HELP with last Challange of Collections ( most_courses)
I tried it for a while now but I just can't make it on my own. I have to create á function that returns the name of the treehouse teacher with the most courses out of a DICT(TEACHER=[COURSES]). Sounds pretty simple but I just don't get how to get the max value out of a list and the max() method just don't want to work, so what am I doing wrong? Thank's for help!
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
# returns the number of teachers
def num_teachers(dic):
teachers = 0
for key in dic.keys():
teachers += 1
return teachers
# returns the absolut number of courses
def num_courses(dic):
courses = 0
for value in dic.values():
courses += len(value)
return courses
# returns all courses added in a single list
def courses(dic):
list = []
count = 0
for value in dic.values():
list.append(value)
other = []
for i in list:
other.extend(i)
return other
# returns the teacher with the most courses
def most_courses(dic):
v = []
len = []
k = []
count = 0
for value in dic.values():
v.append(value)
len.append(len(v[count]))
count += 1
for key in dic.keys():
k.append(key)
return k[len.index(max(len))]
2 Answers
Charlie Gallentine
12,092 PointsHere's how I solved it:
def most_courses(arg):
most_course = 0 # A variable to check if someone has more courses
newTeacher = "" # A place to store their name if they have more
for teacher in arg: # Loops through the given dictionary
if len(arg[teacher]) > most_course: # Checks if one has more courses
most_course = len(arg[teacher]) # Updates who has more
newTeacher = teacher # Updates teacher name
return newTeacher # Returns teacher's name
samuel fiori
4,497 PointsNice code & Thanks for the help!!