Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial2 Answers
Krzysztof Kucharzyk
Front End Web Development Techdegree Student 4,005 PointsFind a line in your code with :
var $dismissButton = $("<button>Dismiss</button>");
and now you have to append the button and save it in $dismissButton to the $modal
$modal.append($dismissButton);
Dustin McCaffree
14,310 PointsLines 5 and 6 of the code read as follows:
var $placeHolder = $("<p id='placeHolder'></p>");
$modal.append($placeHolder);
You need to append the button, just as the $placeHolder was appended.
var $dismissButton = $("<button>Dismiss</button>");
$modal.append($dismissButton);
Without appending the button to the modal, it will never be created and thus cannot be acted upon, using the onclick function.