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Python Python Collections (2016, retired 2019) Sets Set Math

Lindsay Barrett
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.a{fill-rule:evenodd;}techdegree
Lindsay Barrett
Python Web Development Techdegree Student 7,357 Points

Need help with this question

I am not able to solve this problem. Guidance would be appreciated!

sets.py
COURSES = {
    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}
}


def covers(topics):
    list = []
    for course in COURSES:
        if topics & COURSES[course]:
            list.append(course)
    return list 


def covers_all(args):
    new_list[]
    for key, value in COURSES.items:
        if args & COURSES[key] ==args:
            new_list.append(key)
    return new_list

2 Answers

Steven Parker
Steven Parker
229,744 Points

You're really close, but I see two issues:

  • the intialization of "new_list" is missing the operator ("=")
  • the invocation of "COURSES.items()" is missing the parentheses
Lindsay Barrett
seal-mask
.a{fill-rule:evenodd;}techdegree
Lindsay Barrett
Python Web Development Techdegree Student 7,357 Points

Thank you that worked!

def covers_all(args):
    new_list=[]
    for key, value in COURSES.items():
        if args & COURSES[key] ==args:
            new_list.append(key)
    return new_list
Steven Parker
Steven Parker
229,744 Points

Lindsay Barrett — Glad to help. You can mark a question solved by choosing a "best answer".

And for fun and extra practice give Advent of Code a try.

Happy holidays! :christmas_tree: