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# Negating numbers that are spread out

Hi, I am having trouble finding out how to find numbers that are spread out. An example would be trying to find the numbers 1, 5, 7, 9. The code below finds all the numbers from 5-7, but what If i don't want 6? How would I go about it?

negate.py
```import re

string = '1234567890'

good_numbers = re.findall(r'[5-7]', string, re.X)
```

If you're looking to grab the numbers individually you could do something like this:

```re.findall(r"1|5|7|9", string)
```

Or

```re.findall(r"[1579]", string)
```

This will match those digits and prevent grouping them if they're adjacent, e.g. "150" will map to '1' and '5' instead of "15".

Hi Dan,

Thanks for the fast response! The problem I am getting is if I were to do:

```string = "1234567890"
re.findall("[^1579]", string)
```

I'd get back: ['0', '234', '6', '8']

I'd like it to come back as 1 entire string. How do I accomplish this?

Since you'll be dealing with separated groups of numbers I'm thinking something like this would be the easiest solution:

```"".join(re.findall("[^1579]", string))
```

This will capture all the matches as before but concatenate them into one string again.

Thanks Dan! I figured that was the easiest way to do it. If only it came back all at once... haha