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Negative Numbers Task Help
I cant work out why my reg ex is returning numbers in pairs, and misses off the zero at the end?
Please help :(
import re string = '1234567890' good_numbers = (re.findall(r"[\d][^5678]", string))
I was completely overthinking it, the solution was simply: good_numbers = (re.findall(r"[^567]", string))
Chris FreemanTreehouse Moderator 68,029 Points
Glad you worked it out! Working through your original solution, the regex makes the following matches:
- "12" since 2 is not in "5678"
- "34" since 4 is not in "5678"
- skips 5 since 6 is in "5678"
- skips 6 since 7 is in "5678"
- skips 7 since 8 is in "5678"
- "89" since 9 is not in "5678"
- "0" is skipped since there aren't any more characters in pattern