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Python Python Collections (2016, retired 2019) Dictionaries Teacher Stats

Siddharth Pande
Siddharth Pande
9,046 Points

no clue on how to solve this one

no clue on how to solve this one

teachers.py
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(tree_dict):
    intr = len(tree_dict)
    return intr
def num_courses(tree_dict):
    values = list(tree_dict.values())
    count = 0
    for item in values:
        for i in item:
            count += 1
    return count
def courses(tree_dict):
    final_list =[]
    values = tree_dict.values()
    for item in values:
        for i in item:
            print(i)
            final_list.append(i)
    return final_list
def most_courses(tree_dict):

2 Answers

Try having a count set to 0, and a blank string to represent the teacher name. Using "for key,values..." and looping through the dict using the items() method, you can compare the length of the values(courses) to the current count. If it is higher than the current count, assign the key(teacher) to the name string and return that string.

Steven Parker
Steven Parker
229,968 Points

Since you previously returned the count of courses in "num_courses", one approach would be to loop through the items as you did before, but this time keep track of highest count and the teacher associated with it.

Then, when the loop ends, you could return the teacher's name associated with the highest count.