Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialMichael Stopa
14,965 PointsNo comprendo:(
Dear Friends, I do not quite understand which var/function gets precedence when invoked:
var part1 = "Team ";
function bam() { var part2 = "Treehouse"; console.log(part1); }
bam();
2 Answers
Jacob Miller
12,466 PointsSince the function bam
only modifies the variable part2
, the variable part1
is still "Team". Thus when you run bam()
, it will change part2
to "Treehouse" and log "Team" to the console. Because part1
is in the global scope, the function can access it.
If part1
was defined inside a separate function, bam()
would not be able to get it's value and log it to the console.
var part1 = "Team ";
function bam() {
var part2 = "Treehouse";
console.log(part1);
}
bam();
Michael Stopa
14,965 PointsCool! Great thanks for the explanation.