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Python

James Mulholland
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.a{fill-rule:evenodd;}techdegree
James Mulholland
Full Stack JavaScript Techdegree Student 20,944 Points

No idea where I'm going wrong here. Help much appreciated. Here's my code: https://github.com/MulhollandCode/treehouse/

No idea.

lunch.py
from flask import Flask, render_template

app = Flask(__name__)

@app.route('/')
def index():
    class User:
        email = None
    user = User()
    user.email = 'kenneth@teamtreehouse.com'
    return render_template('user.html', user=user)
templates/macro.html
{% macro hide_email(User) %}
    <div>
        {{ hide = User.email[0] }}
        {% for i in range(1, User.email.index('@')) %}
            {{ hide += '*' }}
        {% endfor %}
        {{ hide += `User.email[User.email.index('@'):] }}
        <div>{{ hide }}</div>
    </div>
{% endmacro %}

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points

You are on the right path. Instead of concatenating new characters to hide, simply print them out:

{% macro hide_email(User) %}
        {{ User.email[0] }}
        {% for i in range(1, User.email.index('@')) %}
            {{ '*' }}
        {% endfor %}
        {{ User.email[User.email.index('@'):] }}
{% endmacro %}

This gets you most of the way there: k * * * * * * @treehouse.com, but there are extra spaces. Remove the space by adding minus ("-") signs inside the template tags and variables to indicate no whitespace:

{% macro hide_email(User) %}
        {{ User.email[0] -}}
        {% for i in range(1, User.email.index('@')) %}
            {{- '*' -}}
        {% endfor %}
        {{- User.email[User.email.index('@'):] }}
{% endmacro %}