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Python

Posted by Michael Poehner
Michael Poehner
4,714 Points

'NoneType' object is not subscriptable

'NoneType' object is not subscriptable I am not sure why this is throwing an error in Python web scraping

from urllib.request import urlopen from bs4 import BeautifulSoup

import re

def internal_links(linkURL): html = urlopen('https://treehouse-projects.github.io/horse-land/{}' .format(linkURL)) soup = BeautifulSoup(html, 'html.parser')

return soup.find('a', href=re.compile('(.html)$'))

if name == 'main': urls =internal_links('index.html') while len(urls) > 0: page = urls.attr['href']

    print(page)
    print('\n===============\n')
    urls = internal_links(page)
Mark Chesney
Mark Chesney
11,747 Points

I have an additional question: so is href below just a kwarg made up in that line? Since href isn't normally a predefined parameter to the BeautifulSoup.find() method, I wonder if I understand that right, do I?

return soup.find('a', href=re.compile('(.html)$'))

1 Answer

Michael Poehner
Michael Poehner
4,714 Points
Michael Poehner
Michael Poehner
4,714 Points

I am sorry I just figured it out. I put urls.attr instead of urls.attrs.