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Java Java Basics Perfecting the Prototype String Equality

Posted by Dakota Conway
Dakota Conway
2,869 Points

Not quite sure what to do, having troubles adding in the "IgnoreCase" to this code challenge

Please help, thank you in advance

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample == secondExample) {
  console.printf("first is equal to second");
}
if (firstExample == thirdExample) {
  console.printf("first and third are the same ignoring case");
}

2 Answers

qlpxjevhuv
qlpxjevhuv
10,503 Points
qlpxjevhuv
qlpxjevhuv
10,503 Points

The challenge is expecting you to use the [equalsIgnoreCase](http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#equalsIgnoreCase(java.lang.String\)), as demonstrated in the video, for the second if statement's condition.

ISAIAH S
ISAIAH S
1,409 Points
ISAIAH S
ISAIAH S
1,409 Points

As Tomasz said, you should do something like this:

String example1 = "this is an example";
String example2 = "THIS IS AN EXAMPLE";

if (Example1.equalsIgnoreCase(Example2) {
console.printf("1 is equal to 2");
}

The if statement here would return true, because you are telling it to ignore the case (IgnoreCase).