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Dhruv Ghulati
1,582 PointsNot sure how to create the code for add_list
What am I doing wrong here?
def add_list(list):
while True:
if i>len(list):
break
for i in list:
i=0
return list[i]+list[i+1]
i=i+1
continue
# add_list([1, 2, 3]) should return 6
# summarize([1, 2, 3]) should return "The sum of [1, 2, 3] is 6."
# Note: both functions will only take *one* argument each.
5 Answers
Dhruv Ghulati
1,582 PointsOK I worked it out - basically simpler than we both thought Brian!
def add_list(list):
total=0
for i in list:
total=total+i
return total
Brian Finkelstein
1,767 PointsI think the issue is that every time the for loop goes through a cycle, it sets i=0.
The syntax for num in list: should take care of that for you, I think...
Brian Finkelstein
1,767 PointsCan someone help explain what I'm doing wrong here too?
I keep getting an out of index error but I thought if you use the for something in somethings syntax, it should always know not to go out of bounds.
'''python
def add_list(num_list): while True: sum=0 for item in num_list: if item > len(num_list): break else: sum = sum + num_list[item] print(sum) return(sum)
Call the function with a list
add_list([1, 2, 3]) '''
Kenneth Love
Treehouse Guest TeacherYou both used while True. This is a great construct, but only needed when you want something to run forever (or until explicitly broken with break). You really only want this to run until you run out of things in the list.
Joshua Ridley Joshua Ridley
470 PointsKenneth,
I'm assuming when we type the code we do not know how long or small the list is going to be. How would I create a loop function that knows when to stop with out being explicitly told to?
I thought about asking the user to give the total number of items in the list as the first part of the function, then making a "for" loop that stops at that number, but that would require the input() function.
Kenneth Love
Treehouse Guest TeacherJoshua Ridley Joshua Ridley you just keep going until you get to the end of the list.
for number in range(50):
print(number*2)
for number in range(5000):
print(number/2)
Both of these for loops will run until they run out of numbers. I didn't tell them how to count or anything.
def double(nums):
for num in nums:
print(num*2)
double(range(50))
double(range(5000))
This does the exact same thing but deals with a list (well, list-like object) it doesn't know anything about until it gets to the function.
Joshua Ridley Joshua Ridley
470 PointsAhh, this helps. thanks!
Chris Freeman
Treehouse Moderator 68,423 PointsChris Freeman
Treehouse Moderator 68,423 PointsVery Nice. Much more straight-forward than your original approach.