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Python Python Collections (Retired) Dictionaries Membership

Moses Lagoon
PLUS
Moses Lagoon
Courses Plus Student 660 Points

Not sure how to make this work.

You can check for dictionary membership using the

"key in dict" syntax from lists.

Example

my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}

my_list = ['apples', 'coconuts', 'grapes', 'strawberries']

members(my_dict, my_list) => 2

def members(d, l):

counts.py
# You can check for dictionary membership using the
# "key in dict" syntax from lists.

### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2

def members(d, l): 

3 Answers

Here is the code that passed for me:

def members(dict_map, key_list):
    count = 0
    for item in dict_map:
        for key in key_list:
            if key == item:
                count += 1

    return count

The reason why I named my parameter "dict_map" is because in java (which is what I'm used to) these are called maps, not dictionaries; It helps me remember the structure of dicts.

Avani Agrawal
Avani Agrawal
1,638 Points

Moses, This worked for me-

my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
def members(my_dict, my_list):
    counter = 0
    for item in my_list:
        for key in my_dict:
            if key==item:
                counter += 1

    return counter