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Start your free trialGeorge Akinian
17,615 PointsNot sure how to solve
Sometimes printing out one line won't do. On a new line, use the dir method on the console object to print out the details variable.
I don't know what to do here ...reviewed the video but didn't find any clues
var name = "Andrew";
var details = { favouriteLanguage: "JavaScript", age: 31, children: 2.4 }
var errorMessage = "Something bad has occurred";
console.log(name);
2 Answers
Mathieu HAYS
9,623 PointsYou have to call the 'dir' method from console.
console.dir( yourVariable );
Jeff Ward
8,978 Pointsconsole.log(name);
console.dir(details);
Brian van Vlymen
12,637 PointsBrian van Vlymen
12,637 Pointswhy have to call the 'dir' method? Is part of node.js?
nevermind the next question is answered "Sometimes printing out one line won't do."
manual and documentation is at http://nodejs.org/api/console.html