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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Holden Glass
Holden Glass
6,077 Points

Not sure how to split on more than one parameter

It says that I need to split on not only spaces but I don't know how to split on more that one symbol.

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    words = {}
    stri = string.lower()
    the_string = stri.split(' ')
    for word in the_string:
        if word in words:
            words[word] = words[word] + 1
            words[word] = 1

    return words

2 Answers

By default split splits and all whitespace (spaces, tabs, newlines, etc.)

So the solution is to not pass in any parameters, like this:

# This is only an example

I hope this gives you. :smile:


Holden Glass
Holden Glass
6,077 Points

Yes, thank you. It worked just fine.