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Joeseph Wolfe
Courses Plus Student 1,010 PointsNot sure howto resolve this challenge
I tried to resolve this one by setting up the loop like this: for item in items: if item == 'a': continue print(item)
This works in my interpreter so say if I create a list called item's and I have 'a' assigned to index[0], the if statement will skip it. However this is still giving me a bummer "Didn't find any items being printed...." WEIRD
def loopy(items):
# Code goes here
for item in items:
if item == 'a':
continue
print(item)
1 Answer
Russell Sawyer
Front End Web Development Techdegree Student 15,705 PointsHi Joeseph,
You are very close. The challenge is asking to iterate through the items unless the item with the index[] value of 0 is == to "a".
To check for the 0 index you need to use []. item[0]
def loopy(items):
for item in items:
if item[0] == "a":
continue
else:
print(item)