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Java

Posted by Kae roe
Kae roe
341 Points

not sure what I have wrong here, help?

My task is: "Add another if statement that checks if the firstExample is equal ignoring case to thirdExample. If it, is print out "first and third are the same ignoring case". "

I have:

if (firstExample.equalsIgnoringCase (thirdExample)); { 
   console.printf "(first and third are the same ignoring case"); 
}

It seems right to me since I did the last one which was the same concept. Could this be a glitch or am I missing something small?

4 Answers

Stephen Bone
Stephen Bone
12,359 Points

Hi Greatest

I think your issue here may be the semi-colon immediately after the if statement's closing brace and I've noticed you're missing the opening brace on your printf method too.

EDIT: We also noticed that the string method wasn't quite right so this post has been updated to also reflect that change.

So I think it should be:

if (firstExample.equalsIgnoreCase(thirdExample)) { 
   console.printf("first and third are the same ignoring case"); 
}

Hope it helps but if not let me know and I'll take a closer look.

Stephen

Kae roe
Kae roe
341 Points

Thanks for the fast reply! But I am still getting an error after messing with the semicolon. Also I just realized that when I was typing up the question I missed that brace but in my actual statement I have it there. Just edited it sorry about that

Stephen Bone
Stephen Bone
12,359 Points

No problem. Can you tell me which exercise/task this relates to so I can quickly fire it up?

Also if you're able to post the error it may help point us in the right direction.

Stephen Bone
Stephen Bone
12,359 Points
Stephen Bone
Stephen Bone
12,359 Points

OK so I pasted your original code into the challenge and the issues were with the semi-colon at the end of the if statement conditional (the bit in the braces) and the missing opening brace from the printf method as we discussed earlier.

The bit I didn't pick up on was that the string method is actually equalsIgnoreCase not equalsIgnoringCase. Once I changed that it passed the test.

Here's the code below:

if (firstExample.equalsIgnoreCase(thirdExample)) { 
   console.printf("first and third are the same ignoring case"); 
}

Hope it helps!

Stephen

Kae roe
Kae roe
341 Points

That helped thank you very much. I was copying the wording in the question so that didnt even occur to me haha

Stephen Bone
Stephen Bone
12,359 Points

Yeah! When I looked at it initially I did the same thing :)

Justin Butler
Justin Butler
6,113 Points

if (firstExample.equalsIgnoreCase(thirdExample)) { console.printf("first and third are the same ignoring case"); }

I typed exactly same with you but i still got bummer. Dont know why it did not work

Kae roe
Kae roe
341 Points
Kae roe
Kae roe
341 Points

Android development stage 3 perfecting the prototype string equity http://teamtreehouse.com/library/java-basics/perfecting-the-prototype/string-equality

JavaTester.java:83: error: cannot find symbol if (firstExample.equalsIgnoringCase (thirdExample)); { ^ symbol: method equalsIgnoringCase(String) location: variable firstExample of type String 1 error

Antonio De Rose
Antonio De Rose
20,886 Points
Antonio De Rose
Antonio De Rose
20,886 Points

String firstExample = "hello"; String secondExample = "hello"; String thirdExample = "HELLO";

if (firstExample.equalsIgnoreCase(thirdExample)) { console.printf("first and third are the same ignoring case"); }

Am getting error, what am I doing wrong.