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Java Java Basics Perfecting the Prototype String Equality

Not sure what I'm missing here.

I keep getting a bummer message asking me if I'm using the 'equals' method for 'firstExample' and calling 'console.printf' which I am doing both. Not sure what I'm missing. I also tried using .equalsIgnoreCase from the video and got the same message.

// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample.equals("secondExample")) {console.printf("first is equal to second");}

1 Answer

7,902 Points
// When you used "secondExample" it treated it as a string so it tried to compare it to firstExample
// "hello" == "secondExample" which is not true
// removing the " " fixes the issue because it refers to the secondExample value which is "hello"
// thus making it, "hello" == "hello" 

if (firstExample.equals(secondExample)) {
  console.printf("first is equal to second");

oh I see, thank you!