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![Joeseph Wolfe](https://secure.gravatar.com/avatar/185ebad5c22ef907afaf416d6f1766f0?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Joeseph Wolfe
Courses Plus Student 1,010 PointsNot sure what is wrong here.
I am not quite sure what my hiccup is here.
# You can check for dictionary membership using the
# "key in dict" syntax from lists.
### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
def members(dict_item, list_item):
dict_item = dict(dict_item)
list_item = list(list_item)
for item in list_items:
return len(dict_item[(item)])
1 Answer
![Jeremy Hill](https://uploads.teamtreehouse.com/production/profile-photos/786242/micro_WIN_20151126_150956__2_.jpg)
Jeremy Hill
29,567 PointsHere is what I did:
def members(dictionary, listkeys):
count = 0
for item in dictionary:
for thing in listkeys:
if item == thing:
count +=1
return count
Joeseph Wolfe
Courses Plus Student 1,010 PointsJoeseph Wolfe
Courses Plus Student 1,010 PointsThanks Jeremey, I see what I did wrong here. (I needed a second for loop and I wasn't doing a if statement to compare what was in the dict with the items in the list.
Thanks again !