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Python Python Collections (Retired) Dictionaries Membership

Posted by Joeseph Wolfe
Joeseph Wolfe
Courses Plus Student 1,010 Points

Not sure what is wrong here.

I am not quite sure what my hiccup is here.

counts.py 
# You can check for dictionary membership using the
# "key in dict" syntax from lists.

### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2

def members(dict_item, list_item):
    dict_item = dict(dict_item)
    list_item = list(list_item)
    for item in list_items:
        return len(dict_item[(item)])

1 Answer

Jeremy Hill
Jeremy Hill
29,567 Points

Here is what I did:

def members(dictionary, listkeys):
    count = 0
    for item in dictionary:
        for thing in listkeys:
            if item == thing:
                count +=1

    return count
Joeseph Wolfe
Joeseph Wolfe
Courses Plus Student 1,010 Points

Thanks Jeremey, I see what I did wrong here. (I needed a second for loop and I wasn't doing a if statement to compare what was in the dict with the items in the list.

Thanks again !