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Java Java Basics Perfecting the Prototype String Equality

Not sure what is wrong with this section code. any help appreciated!

Not sure what the error means.

// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
if (firstExample.equals("secondExample"))
  console.printf("first is equal to second");
String secondExample = "hello";
String thirdExample = "HELLO";

3 Answers

George S-T
George S-T
6,624 Points

Try removing the quotation marks surrounding secondExample: (firstExample.equals(secondExample))

Instead of

if (firstExample.equals("secondExample"))

you have to write

if (firstExample.equals(secondExample))

In this situation you are comparing whether the string "hello" equals the string "secondExample" because you put quotation marks around the secondExample variable, which becomes a string instead of being a variable.

In other words, removing the quotation marks from secondExample, you are referring to the (string) value of your secondExample string variable. In this case hello equals hello. Otherwise, hello does not equal secondExample.

Great, Thanks!

Best answer would be appreciated :-)