Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript and the DOM (Retiring) Getting a Handle on the DOM Selecting Multiple Elements

Jaimin Patel
Jaimin Patel
9,020 Points

Not sure what to do

I tried to look into this and I'm confused by what it wants me to do and I don't know how to proceed with it.

js/app.js
var listItems;
var colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];

for(var i = 0; i < colors.length; i ++) {
  listItems[i].style.color = colors[i];    
}
index.html
<!DOCTYPE html>
<html>
  <head>
    <title>Rainbow!</title>
  </head>
  <body>
    <ul id="rainbow">
      <li>This should be red</li>
      <li>This should be orange</li>
      <li>This should be yellow</li>
      <li>This should be green</li>
      <li>This should be blue</li>
      <li>This should be indigo</li>
      <li>This should be violet</li>
    </ul>
    <script src="js/app.js"></script>
  </body>
</html>

1 Answer

Steven Parker
Steven Parker
231,269 Points

On the very top line, the "listItems" needs to be given a value in addition to being declared as a variable. The "querySelectorAll" method used with a descendant selector argument might come in handy to doing this.

Jaimin Patel
Jaimin Patel
9,020 Points

I seriously don't know what you talking about can you send me code example? I want to go through and understand that.

Steven Parker
Steven Parker
231,269 Points

You may want to look at this answer I gave to a similar question. Just be aware that there is more than one possible solution.