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C# C# Basics (Retired) Perfect if / else if / else

Posted by Matt L
Matt L
1,030 Points

Not sure whats wrong.

string input = Console.ReadLine(); int temperature = int.Parse(input);

if(temperature <= 21) { Console.WriteLine("Too cold!"); } else if (temperature => 21 && <= 22) { Console.WriteLine("Just right."); } else if(temperature > 22) { Console.WireLine("Too hot!"); }

CodeChallenge.cs 
string input = Console.ReadLine();
int temperature = int.Parse(input);

if(temperature <= 21)
{
Console.WriteLine("Too cold!");
}
else if (temperature => 21 && <= 22)
{
Console.WriteLine("Just right.");
}
else if(temperature > 22)
{
Console.WireLine("Too hot!");
}

5 Answers

bothxp
bothxp
16,510 Points

Hi Matt,

Have a think about:

if(temperature < 21){
  Console.WriteLine("Too cold!");
} else if (temperature <= 22){
  Console.WriteLine("Just right.");
} else {
  Console.WriteLine("Too hot!");
}

Make sure that you are only getting the "Too cold!" message if the temperature is less than 21 (not also equal to it). You only need 1 'else if' and you don't need to use the && because you will only get to this test if the temperature is 21 or above due to the test in the original 'if'. Then at the end you only need to use an 'else'.

Matt L
Matt L
1,030 Points
Matt L
Matt L
1,030 Points

This is the error I get. No clue what it means. A local variable named setting' cannot be declared in this scope because it would give a different meaning tosetting', which is already used in a `parent or current' scope to denote something else

Eric Moody
Eric Moody
12,373 Points
Eric Moody
Eric Moody
12,373 Points 
if (temperature >= 21 && temperature <= 22)
{
  Console.WriteLine("Just right.");
}

You're using => which is a Lambda operator which doesn't mean what you intend. Also you need to have the temperature compared on both sides of the &&

Matt L
Matt L
1,030 Points
Matt L
Matt L
1,030 Points

OK thanks!

Matt L
Matt L
1,030 Points
Matt L
Matt L
1,030 Points

Thanks for the explanation.