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Java Java Basics Perfecting the Prototype String Equality

Not sure where I went wrong

Not showing up as error on the previews. So not sure where the errors are

// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
if (secondExample.equals("hello")){
  console.printf("first is equal to second.");
String thirdExample = "HELLO";

Question was Add an if statement that checks to see if firstExample is equal to secondExample. If it is, print out "first is equal to second".

1 Answer

Simon Coates
Simon Coates
4,968 Points

The exit statement is probably messing things up. Moving the third string further up would make sure it is assigned a value, but doesn't seem to alter whether it passes validation. So I'd guess the exit short-circuits their validation code.