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Jesse Miller
7,920 PointsNot sure where I'm going wrong for courses(dicts) (Last part of challenge).
Did I go wron gin my if else statement?
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
def most_classes(dicts):
most_class = "" # holds the name of teach with most class
max_count = 0 # max counter for classes
for teacher in dicts:
if len(dicts[teacher]) > max_count:
max_count = len(dicts[teacher])
most_class = teacher
return most_class
def num_teachers(dicts):
num = 0
for i in dicts:
num+=1
return num
def stats(dicts):
list_of_lists = []
for i in dicts:
for q in dicts[i]:
list_of_lists.append([i, len(dicts[i])])
return list_of_lists
def stats(dicts):
list_of_lists = []
for i in dicts:
for q in dicts[i]:
list_of_lists.append([i, len(dicts[i])])
return list_of_lists
def courses(dicts):
single = []
for i in dicts:
for q in dicts[i]:
if q not in single:
single.append(dicts[i][q])
else:
continue
return single
2 Answers
Aby Abraham
Courses Plus Student 12,531 Pointsdef most_classes(dict):
max_count = 0
str = ""
alist = dict.values()
for key, value in dict.items():
if len(value) > max_count:
max_count = len(value)
str = key
return str
def num_teachers(dict):
return len(dict.keys())
def stats(dict):
slist = []
for key, value in dict.items():
slist.append([key, len(value)])
return slist
def courses(dict):
clist = []
for value in dict.values():
clist.extend(value)
return clist
Steven Parker
231,269 PointsHere's a few hints:
- you have defined the stats function two times (oddly, that doesn't actually affect the challenge checker)
- it looks like you have an indentation error starting at:
if q not in single: - your append is trying to use strings as numeric indices (did you mean to write:
single.append(q)?)
When you fix these, I think you'll have it.
T K
21,479 PointsI'd also add that, while adding the if statement is a great idea and will work, it's not actually needed to pass this challenge.
Also, this won't effect the challenge but single letter variables like i and q aren't very "Pythonistic". You should aim to use descriptive variables! like
def course(teachers):
course_list = []
for teacher in teachers:
for course in teacher:
#etc etc
Good luck!
Tayler
Steven Parker
231,269 PointsAbout that if statement: the challenge does not use the same data as in the example to test your function, so we don't know for sure if having it would make a difference before trying it (but as Tayler says, it doesn't).
However, the challenge was not specific about making the list unique names or not. If the object were to create a list of unique names, the if statement would be important. On the other hand, if the object were to compile a cumulative list, the if statement would need to go. We just don't know, but I think your choice of a unique list is the more practical one.