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Start your free trialWilliam Lee
1,316 PointsNot sure where the error is
Yep
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
switch n {
case n % 3 = 0: return "Fizz"
case n % 5 = 0: return "Buzz"
case n % 3 == 0 && n % 5 == 0: return "FizzBuzz"
}
// End code
return "\(n)"
}
1 Answer
Steve Hunter
57,712 PointsHi William,
To use a switch
statement, you need to add additional conditions as the switch effectively pivots on a value of n
which isn't what you want. The switch
of n
would define coded routes for each value, or group of values, of n
, rather than involving any further manipulation. It is possible, though, with some messing about!
Personally, I'd use a chained if
statement for this particular challenge which I'll show you below.
Further, remember that a switch
, or an if
will return immediately a result is found. So, do the combined test first, i.e. the test of both 3 & 5. Otherwise, if n
is 15, the first statement is true (15 % 3 == 0
) and you get "Fizz" returned.
Here's one way of using a switch
, which isn't pretty:
switch n {
case n where (n % 5 == 0 ) && (n % 3 == 0): return "FizzBuzz"
case n where (n % 3 == 0): return "Fizz"
case n where (n % 5 == 0): return "Buzz"
default: break
}
The nested if
statement would look like:
if n % 3 == 0 && n % 5 == 0{
return "FizzBuzz"
} else if n % 3 == 0{
return "Fizz"
} else if n % 5 == 0{
return "Buzz"
}
I hope that helps.
Steve.