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# Not sure why I'm not getting the right answer.

Can someone take a look at my code and let me know what I'm doing incorrectly?

squared.py
```# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
try:
parsed_int = int(num)
except ValueError:
return num
return parsed_int * parsed_int
```

The challenge is asking you to multiply a number by itself, or square the number, and return the value. If the number introduced to the function can't be converted to an integer, meaning it's a string, then return the string the same amount of times as the letters in the string.

Keep in mind you need to return a value in the try: section

You also only need one return value in the except ValueError: section

```def squared(number):
try:
return int(number)**2
except ValueError:
return number * len(number)
```

ahh, misread the direction. Thanks guys!

PLUS

Here is another way to approach it:

# squared("tim") would return "timtimtim"

def squared(a): try: a = int(a) a = a * a except ValueError: a = a * len(a) return a