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Python Python Basics (2015) Number Game App Squared

Posted by diegoholt
diegoholt
1,076 Points

Not sure why I'm not getting the right answer.

Can someone take a look at my code and let me know what I'm doing incorrectly?

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
    try:
        parsed_int = int(num)
    except ValueError:
        return num
    return parsed_int * parsed_int
Russell Sawyer
seal-mask
.a{fill-rule:evenodd;}techdegree
Russell Sawyer
Front End Web Development Techdegree Student 15,705 Points
Russell Sawyer
.a{fill-rule:evenodd;}techdegree
Russell Sawyer
Front End Web Development Techdegree Student 15,705 Points

The challenge is asking you to multiply a number by itself, or square the number, and return the value. If the number introduced to the function can't be converted to an integer, meaning it's a string, then return the string the same amount of times as the letters in the string.

Keep in mind you need to return a value in the try: section

You also only need one return value in the except ValueError: section

def squared(number):
    try:
        return int(number)**2
    except ValueError:
        return number * len(number)
diegoholt
diegoholt
1,076 Points

ahh, misread the direction. Thanks guys!

1 Answer

Cindy Lea
PLUS
Cindy Lea
Courses Plus Student 6,497 Points
Cindy Lea
Cindy Lea
Courses Plus Student 6,497 Points

Here is another way to approach it:

EXAMPLES

squared(5) would return 25

squared("2") would return 4

squared("tim") would return "timtimtim"

def squared(a): try: a = int(a) a = a * a except ValueError: a = a * len(a) return a