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Python Python Collections (2016, retired 2019) Tuples Combo

victor E
victor E
19,145 Points

not sure why this isn't working.

the example it shows as my output seems correct

# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
def combo(item1, item2):
    combined = []
    for i in range(0, len(item1)):
    return combined
Kyrylo Troian
Kyrylo Troian
570 Points

You are generating an index with for in, but you use constant 1 as an index from item2. for in loop works with iterable and generator objects, range is a generator function and list is iterable. You can simplify working with lists:

for n in items:

Also, think about renaming variables item1 and item2, item_1and item_2 or numbers and characters will be better.

For your needs, you may use zip():

combined = list()
    for i, j in zip(item_1, item_2):
        combined.append((i, j))
    return combined
victor E
victor E
19,145 Points

Kyrylo, thank you that does work for the desired problem but it does not want me to use zip. this is the message it gives me lol

Bummer: Don't use zip()! I know it exists but the point of this challenge is to solve the problem yourself.

1 Answer

Steven Parker
Steven Parker
229,981 Points

It looks like you just have a typo. The index for item2 is a 1 (one) instead of the letter "i":

        combined.append((item1[i],item2[1]))    # original code
        combined.append((item1[i],item2[i]))    # fixed

Note that the "bummer" message doesn't show your output, but an example of what it is expecting.