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PHP PHP Functions Introducing Functions PHP Function Arguments

lewis tibbott
lewis tibbott
1,754 Points

Not the same output


function hello($arr) {

if (is_array($arr)) {
    foreach ($arr as $name){
        echo "Hello $name <br>";
} else {
    echo "Hello";


$names = array("name1, name2, name3"); hello($names); ?>

When I run my code the output is hello name1 name2 name3 when it should be hello name1 hello name2 hello name3

I don't understand why its working like this, could someone please explain?

1 Answer

The array items are strings and each one of them has to wrapped inside quotes, now you have all of them wrapped in one pair of quotes.

// Your code
$names = array("name1, name2, name3");

// Change it to this
$names = array("name1", "name2", "name3");