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Deanna Morale
4,138 PointsNow let's add another flavor to the ice cream store. Add a fourth element to the array with a value of "Cookie Dough" (my personal favorite). When you preview the code, notice that the count of flavors increases and the new flavor is added to the list aut
Will someone help me, I'm going on 3 hours on one code challenge.
Question: Now let's add another flavor to the ice cream store. Add a fourth element to the array with a value of "Cookie Dough" (my personal favorite). When you preview the code, notice that the count of flavors increases and the new flavor is added to the list automatically.
My answer:
<?php $flavors = array
("Chocolate", "Vanilla", "Caramel", "Cookie Dough");
?>
<p>Welcome to Ye Olde Ice Cream Shoppe.
We sell <?php echo count($flavors);
?>flavors of ice cream.</p>
<ul>
<li><?php foreach ($flavors as $flavor) { ?>
<?php echo $flavor; ?></li></ul>
<?php } ?>
1 Answer
Keith Kelly
21,326 PointsYour foreach loop should be in an unordered list like this:
<ul>
<?php foreach($flavors as $flavor) { ?>
<li><?php echo $flavor; ?></li>
<?php } ?>
</ul>
Or did your HTML just not post?
Deanna Morale
4,138 PointsDeanna Morale
4,138 PointsThanks Keith, I appreciate it! I wound up figuring it out last night after 4 hours(not kidding) lol...In fact Im not even sure how. I didn't even know this post successfully posted:)
Keith Kelly
21,326 PointsKeith Kelly
21,326 PointsNo problem, glad you got it working!