Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Android Build a Simple Android App (retired 2014) Learning the Language Objects and Random Numbers

Now limit the range of the randomNumber variable from 0 to 9. Use the version of 'nextInt()' that has a parameter that s

I don't know what's wrong??

3 Answers

Ben Jakuben
STAFF
Ben Jakuben
Treehouse Teacher

Hi David Bell, can you post in the code you are trying? I have a hunch that you might just need to change the number you're using to generate the random number.

Joshua Scott
Joshua Scott
540 Points

Hey Ben, love the course, but I'm having a little trouble with this part. Here's my code so far:

Random randomGenerator = new Random();
int randomNumber = randomGenerator.nextInt(9);
answer = Integer.toString(randomNumber);
Ben Jakuben
Ben Jakuben
Treehouse Teacher

Ah, you're skipping ahead! Remove that last line (or comment it out) and you'll receive a helpful error message about your second line.

I have the same problem, my code is:

Random randomGenerator = new Random();

int randomNumber = randomGenerator.nextInt(10);

intAsString = Integer.toString(randomNumber);

randomGenerator.nextInt(3); gives your a number between 0 and 2 randomGenerator.nextInt(10); gives you a number between 0 and 9

that answer from @Roman Mayer