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Android Build a Simple Android App (retired 2014) Learning the Language Objects and Random Numbers

Now limit the range of the randomNumber variable from 0 to 9. Use the version of 'nextInt()' that has a parameter that s

I don't know what's wrong??

3 Answers

Ben Jakuben
STAFF
Ben Jakuben
Treehouse Teacher

Hi David Bell, can you post in the code you are trying? I have a hunch that you might just need to change the number you're using to generate the random number.

Joshua Scott
Joshua Scott
540 Points

Hey Ben, love the course, but I'm having a little trouble with this part. Here's my code so far:

Random randomGenerator = new Random();
int randomNumber = randomGenerator.nextInt(9);
answer = Integer.toString(randomNumber);
Ben Jakuben
Ben Jakuben
Treehouse Teacher

Ah, you're skipping ahead! Remove that last line (or comment it out) and you'll receive a helpful error message about your second line.

I have the same problem, my code is:

Random randomGenerator = new Random();

int randomNumber = randomGenerator.nextInt(10);

intAsString = Integer.toString(randomNumber);

randomGenerator.nextInt(3); gives your a number between 0 and 2 randomGenerator.nextInt(10); gives you a number between 0 and 9

that answer from @Roman Mayer