Now limit the range of the randomNumber variable from 0 to 9. Use the version of nextInt() that takes a parameter specif

nextInt(3) will only give you a number from 0 to 2, not 0 to 9. You want to use a number that will let nextInt give you a result of 0 to 9.

Random randomGenerator = new Random(); int randomNumber = randomGenerator.nextInt(0);

I have a question: Why this one work: 1. Random randomGenerator = new Random(); int randomNumber = randomGenerator.nextInt(10); but this one doesn't work: 2. Random randomGenerator = new Random(); int randomNumber = randomGenerator.nextInt(n:10); I thought I saw the lecturer did the method 2 in the video. But when I put n:10, it did not work so I changed to method 1: (10) and it worked. many thanks for the explanation!

I don't want to give you the answer outright, but let's try this: I'll give you all the pieces you need for that final line, and you'll just need to figure out how to configure them in the right way to meet that last requirement.

String 
intAsString 
= 
randomNumber 
+ 
""
;

Remember that you'll start by declaring a variable named intAsString. You need the type to be String. Then you set it equal to something. In this case you want to set it to the random number stored in a variable. But since that number is an int type, you need to convert it to a String, which you can do using the same shortcut like we did in the previous video.