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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by Charon knight
Charon knight
3,306 Points

Now replace <YOUR NAME> in the console.printf expression with the firstName variable using the string formatter. how?

im stuck on this part! I'm not understanding what I'm doing wrong.

Name.java 
String firstName = "firstName";

  console.printf("Hello, my name is %s\n", firstName);
  console.printf("firstName can code in java!\n");

2 Answers

Michael Chan
Michael Chan
15,252 Points
Michael Chan
Michael Chan
15,252 Points

Hello Charon,

There are three parts to the challenge - the first part is just declaring a string with your first name, which you've got.

String firstName = "firstName";

The second part is using console to print out a string without using the variable.

console.printf("<firstName> can code in Java!");

The third is where you'll have to substitute the <firstName> portion in part two with your string variable created in part one. I'll leave this last part for you. Let me know if you need further clarifications.

Keshav Patel
Keshav Patel
494 Points
Keshav Patel
Keshav Patel
494 Points

how do i do the third that is the part i don't get

Opeyemi OLORUNLEKE
Opeyemi OLORUNLEKE
269 Points

? i still don't get

Opeyemi OLORUNLEKE
Opeyemi OLORUNLEKE
269 Points
Opeyemi OLORUNLEKE
Opeyemi OLORUNLEKE
269 Points

Now, i get it To my Juniors :), Try calling the string Variable in different statements as shown below

String firstName = "Micklo"; console.printf("Hello, my name is %s\n",firstName); console.printf("I %s am learning Java\n",firstName); console.printf("%s is talking in third person\n",firstName); console.printf("%s hopes these commands are expressed correctly\n",firstName); console.printf("%s can code in Java!",firstName);