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Siddhant Dahiya
156 PointsNow replace your name with the firstname variable using the string formatter
console.printf("my name is %s/n, firstName"); String firstName = ("sid"); console.printf("%s can code in Java/n, firstName");
its not working what wrong with this?
1 Answer

Dan Johnson
40,532 PointsSince you have quotes around the comma and firstName variable, it's treating the entire thing as one string. printf is expecting the first argument to be the string you want to format, and the following argument(s) to be the values to fill the placeholders with. So you'll want to write it like this:
String firstName = "YourName";
console.printf("%s can code in Java!", firstName);