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Android Build an Interactive Story App (Retired) Finishing the User Interface Using a Model in the Controller

Now that we have a model object, update the TextView to use the Spaceship's type property. Challenge HELP

How do i do this?

import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class LandingActivity extends Activity {

    public Button mThrustButton;
    public TextView mTypeLabel;
    public EditText mPassengersField;

    public Spaceship mSpaceship;

    public void onCreate(Bundle savedInstanceState) {

        mThrustButton = (Button)findViewById(R.id.thrustButton);
        mTypeLabel = (TextView)findViewById(R.id.typeTextView);
        mPassengersField = (EditText)findViewById(R.id.passengersEditText);

        // Add your code here!
      mSpaceship = new Spaceship("FIREFLY");
      String type = Spaceship.getType();
      mTypeLabel = setText(type);
public class Spaceship {
    private String mType;
    private int mNumPassengers = 0;

    public String getType() {
      return mType;

    public void setType(String type) {
      mType = type;

    public int getNumPassengers() {
      return mNumPassengers;

    public void setNumPassengers(int numPassengers) {
      mNumPassengers = numPassengers;

    public Spaceship() {
      mType = "SHUTTLE";

    public Spaceship(String type) {
      mType = type;

2 Answers

Hi Saeed,

You're very close with that! Just a couple of things; setText is a method that works on the TextView so you use dot notation for that. Also, the getType method should be called on the instance of Spaceship not the class directly, so use mSpaceship not Spaceship.

mSpaceship = new Spaceship("FIREFLY");

You could equally do this on more than one line, as you have done:

String type = mSpaceship.getType();

I hope that helps,


Thank you very much Steve Hunter. Excellent explanation! Helped me plenty :-)

No problem - glad to help! :-)