Number Game Refinement Queston

Question

Hello,

I have in issue with validating user input: if non integer is inserted, program crashes: looks like input_validation() doesn't work. First part of this function is working, since we are calling it from main_body() function and even passing a message as a string. Why "except" part doesn't work?

Additionally, once game is over (either user guessed the number or lost) - how to let the user start the game again?

Thanks :)

def number_generator():
    import random

    # generate a random number between 1 and 10
    random_num = random.randint(1, 10)
    print("......")
    print("Random number has been generated.")
    print("......")
    return random_num


#validating if number is an integer
def input_validation(message):
    while True:
        try:
            player_input = int(input(message))
        except ValueError:
            print("That's not a number, please try again")
            continue
        else:
            return player_input
            break

def main_body():
    #introduction
    number_of_tries = 6
    print("Hello, this is a Random Number Guessing Game. You will have {} tries to guess a random number in range from 1 to 10.".format(number_of_tries))
    random_num = number_generator()
    while number_of_tries > 0:
        # getting a number guess from the player
        # making sure it's an integer
            player_input = input_validation("Guess a number between 1 and 10: ")

            # compare guess to secret number
            if player_input == random_num:
                print("You selected {} and computer also selected {} - Congrats!".format(player_input, random_num))
                break
            elif player_input > random_num:
                number_of_tries = number_of_tries - 1
                print("Aim lower, but remember that you have {} tries left.".format(number_of_tries))
            elif player_input < random_num:
                number_of_tries = number_of_tries - 1
                print("Aim higher, but remember that you have {} tries left.".format(number_of_tries))
            else:
                number_of_tries = number_of_tries - 1
                print("Wrong! You now have {} tries left.".format(number_of_tries))
    else:
        print("You've lost! No tries left. ")

main_body()

    # catch if someone catches a non-integer
    # let people play again

Answer 1 · 2017-01-30T04:11:54Z

January 30, 2017 4:11am

What you have here seems to work for me. If I type 'asdf' the exception says "That's not a number, please try again." as it should.

To allow the user to play again, I would create a function that is called where ever the game is currently ended now. The function would look something like this:

def play_again():
    while True:
        player_input = input("Would you like to play again? Y / n ")
        if player_input.lower() not in 'yn':
            continue
        elif player_input.lower() == 'y':
            main_body()
        else:
            break

When the player types 'y' the function will call main_body() again and the game will start over; otherwise, the game is ended by breaking the while loop and not having anything else to run.

I would place a call to the 'play_again()' function in two places. I would replace the 'break' in the if statement if the player guesses correctly and I would call it just below the 'print()' in the final 'else:' statement when the player loses.

Let me know if this helps or if you need further clarification.

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maxmaltsev

maxmaltsev

Number Game Refinement Queston

1 Answer

Dustin James

Dustin James