Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Python Python Basics (2015) Number Game App Number Game Refinement

Shayan Salehi
Shayan Salehi
1,033 Points
Posted by Shayan Salehi
Shayan Salehi
1,033 Points

Number game - SyntaxError: 'break' outside loop

import random

generate random number 1 and 10

secret_num = random.randint(1, 10)

while True:

number guess from the player

guess = int(input("Guess the number between one and ten: "))

compare guess to secret number

if guess == secret_num: print("my number was indeed {}".format(secret_num)) break

else:
print("Wrong :(")

print hit or miss

When I run the script I get the following error:

treehouse:~/workspace$ python numgame.py
File "numgame.py", line 14
break
^
SyntaxError: 'break' outside loop

1 Answer

Christian Mangeng
Christian Mangeng
15,969 Points
Christian Mangeng
Christian Mangeng
15,969 Points

Hi Shayan,

it seems to be a problem of the correct spacing. With the "break" command you break out of the "while" loop, so break has to be inside the while loop. This should work:

import random

secret_num = random.randint(1, 10)

while True:

    guess = int(input("Guess the number between one and ten: "))

    if guess == secret_num:
        print("my number was indeed {}".format(secret_num))
        break

    else:
        print("Wrong")