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JavaScript JavaScript Foundations Numbers Operators

Posted by Jacinda Zhong
Jacinda Zhong
3,695 Points

Numbers - code not working

I have absolutely no clue why this code isn't working, and I started adding lots of parentheses just in case, but still it didn't work...Help!

  var three = (a + b);
  var ten = (a + c) * b;
  var nineteen = ((c*c) + a + b);
  var onehundred = ((c**c)**c) + (b**c) + (c * (c+a));

2 Answers

Dave McFarland
STAFF
Dave McFarland
Treehouse Teacher
Dave McFarland
Dave McFarland
Treehouse Teacher

The problem is this line of code: 

var onehundred = ((c**c)**c) + (b**c) + (c * (c+a));

There's no ** operator in JavaScript. To raise a number to the power of another number you use the Math.pow() method. So to get c^b you'd write this Math.pow(c,b)

The challenge is asking for you to use common numeric operators -- + - * / % -- anyway so skip the Math.pow() method.

Jacinda Zhong
Jacinda Zhong
3,695 Points

I see! That's odd that there isn't an operator for exponents. Thanks Dave!

Adam Sackfield
PLUS
Adam Sackfield
Courses Plus Student 19,663 Points
Adam Sackfield
Adam Sackfield
Courses Plus Student 19,663 Points

Try this (not sure what the a,b,c represents so will use 1 2 3) you will need to change to letters

    var three = 1 + 2
    var ten = (2 + 2 + 1) * 2
    var nineteen = (3 * 3) + (2 + 2 + 2 + 2 + 2)
    etc

Just remember that things in parentheses are evaluated first.

Jacinda Zhong
Jacinda Zhong
3,695 Points

I see! I didn't realize that there isn't an operator for exponents. Thanks Adam!