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Stan Shyshkin
8,629 PointsObjective C Basics - Pointers & Memory Code Challenge
Hi,
I'm having trouble with the following from the Objective C - Pointers & Memory Code Challenge (task 2).
Using the printf function print the size in bytes of the variable "real_numbers". Your output should look like the following: "Array real_numbers is x bytes."
What I have is:
float real_numbers [] {1.1, 1.2, 1.3, 1.4, 1.5};
printf("Array real_numbers is %ld bytes."\n, sizeof(float));
return 0;
& my error message is:
Bummer! Make sure you are calling printf and passing a string (not an NSString) and "real_numbers" as the parameters. The correct format option is '%ld'.
Any suggestions on what I'm doing wrong?
5 Answers
bradley
4,267 PointsHi Stan
You want to do a sizeof(real_number) not float.
Stan Shyshkin
8,629 PointsHey Bradley,
Thanks! It looks like I had it confused with the second section of the example in the video. But does the float go for the 3rd part?
I'm having trouble with the next step, which is:
Print the length of the array "real_numbers" using the sizeof() function. Your output should look like the following: "Array real_numbers can store x items."
I have
float real_numbers [5];
printf("Array real_numbers is %ld bytes.", sizeof(real_numbers));
printf("Array real_numbers can store %ld items.", sizeof(float));
which also comes out incorrect.
*****Never mind - got it.
Part 3 is basically sizeof(real_numbers)/sizeof(float))
Turd Furgeson
2,579 PointsI am tearing my hair out with this one in my ipad.
I'm entering:
float real_numbers [5] = {}; printf("Array real_numbers can store %ld items/n", sizeof(real_numbers)/sizeof(float));
It keeps marking it down and saying real_numbers is long and asking if I'm using %ld, which I am. I feel like I'm understanding the concept and what's going on.
Any tips on what I've got wrong?
Thanks
bradley
4,267 PointsHey Turd after items you have /n. For a newline character this should be \n after items don't know if this will fix your problem
Turd Furgeson
2,579 PointsThanks, bradley!