Rafael Maida2,307 Points
i am looking to create a fucntion that determines if a number is even/odd
def is_odd (num): (float(num) % 2) > 0
Steven Parker177,523 Points
You're really close! You just need a "return" keyword to give your result back to the caller.
Also, while it won't affect passing the challenge, you don't need to convert the number with "float".