Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.
i am looking to create a fucntion that determines if a number is even/odd
def is_odd (num): (float(num) % 2) > 0
Steven Parker216,719 Points
You're really close! You just need a "return" keyword to give your result back to the caller.
Also, while it won't affect passing the challenge, you don't need to convert the number with "float".