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Python Python Collections (2016, retired 2019) Lists Disemvowel

Posted by mamadou diene
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mamadou diene
Python Web Development Techdegree Student 1,971 Points

OK, I need you to finish writing a function for me. The function disemvowel takes a single word as a parameter and then

Help please. i need pointers on this one

disemvowel.py 
char word = "treehouse"
vowels = ("a", "e", "i", "o", "u")

    def disemvowel(word):
    try:
        word.remove(vowels).lower() or word.remove(vowels).upper()
        except ValueError:
            pass            
        return word

1 Answer

Valeriya Romashchenko
Valeriya Romashchenko
11,841 Points
Valeriya Romashchenko
Valeriya Romashchenko
11,841 Points

Hello!

Your code has several problems like:

  1. When you define the variable it should be one word : "char word" ===> "char_word";
  2. Be careful about indentation in python. At least it should look like:
char_word = "treehouse"
vowels = ("a", "e", "i", "o", "u")
def disemvowel(word):
    try:
        word.remove(vowels).lower() or word.remove(vowels).upper()
    except ValueError:
            pass            
    return word
  1. You store your vowel in the tuple, not in the list. I don't know did you made on purpose, or you intended to make a list: python vowels = ["a", "e", "i", "o","u"]

  2. Also, .remove() is a list method, and you apply it for the string. from python docs:

    list.remove(x)
Remove the first item from the list whose value is x. It is an error if there is no such item.

  3. I don't see the reason to use here try-except block. You don't need to validate the users' input, check if it is string or integer etc. Here you can just iterate through the word and check if the letter is vowel or not. If it is a vowel - ignore, if not - keep the letter.

This challenge says that we can solve this task however we want. My code like this passed the challenge:

def disemvowel(word):
    result_word = []  # I am creating an empty list where I am going to store letters that are not vowels
    vowels = ["a", "e", "i", "o","u"]  # list of vowels which is going to help find all vowels in the word
    for letter in word:  # I want to check every letter in the word and iterate with for loop through the word
        if letter.lower() not in vowels:  # I check if the letter not in the list of the vowels
            result_word.append(letter)  # if it is NOT, I append to my empty list the letter that is not in the vowels list
    return ''.join(result_word)  # I return the result list as a string by joining all elements in the list without any condition

Don't be discouraged! I am a different person and our logic can vary in the approaching the problem. If you can solve this with try-except block, share your code, please)