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Python

Ok, so this is my first Python code ever. It does okay but the def ask_again function keeps returning an error.

It returns an error and won't even prompt a "yes/no" response from the user. How can I resolve this? Any input would be most helpful...thanks!

def factorial(n):
      if n <= 0:
            return 0
      elif n == 1:
            return 1
      else:
            fact = 1
            while(n > 1):
                  fact *= n
                  n -= 1
            return fact
def getNumberFromUser():
      num = int(input("Please input whole a number under 11: "))
      if (num <= 10):
            return num
      else:
            print ("Sorry wrong number!")
            return -1
def ask_again():
      cont = ''

      while cont not in ("yes", "no"):

            cont = input("Another one?(yes/no)  ").lower()
            if cont == "yes":
                  return cont

            else:
                  break
#print("You chose",num)

while True:
      result = -1
      while (result < 0):
            result = getNumberFromUser()
      fact = factorial(result)
      print("Factorial of ", result, "is", fact)

[MOD: added ```python formatting -cf]

Hey I'm also new to Python too. This is a great course. For this problem is there a way we can see the entire code. If you're working in a work space there's a button at the left of the workspace that takes a snapshot of your code. You can copy and paste it on here. That way we can look at the syntax as well as the error. Thank you.

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,426 Points

I can not cause the error you are seeing. The code runs as-is. There does not seem to be a call to execute ask_again