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Python Introducing Lists Build an Application Multidimensional Musical Groups

Robson Possidonio
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.a{fill-rule:evenodd;}techdegree
Robson Possidonio
Python Development Techdegree Student 657 Points

one way to answer?

I think I've figured out another way to solve this task, but I keep getting an error. are alternative answers a no no?

groups.py
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
# Your code here

def test(params):
    for param in params:
        print(*param, sep = ", ")


test(musical_groups)

2 Answers

Steven Parker
Steven Parker
216,812 Points

Some challenges are as much about practicing a specific method as they are about producing the expected output. The instructions in this case asked you to "output the members joined together with a ", " comma space as a separator".

Your approach would produce the same output but it doesn't join the members together (using the "join" string method).