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JavaScript JavaScript Loops, Arrays and Objects Tracking Data Using Objects The Student Record Search Challenge Solution

Saqib Ishfaq
Saqib Ishfaq
13,912 Points

only one student name prints for me, one i type in the end. even though the code exactly the same!

var student;
var search;
var message = '';
function print(message) {
    var outputDiv = document.getElementById('output');
    outputDiv.innerHTML = message;
  }
  function getStudentRecord(student){
    var report = '<h2>student: ' +student.name+ '</h2>';
    report += '<p>track: '+ student.track+ '</p>';
    report += '<p>achievements: ' +student.achievements+ '</p>';
    report += '<p> points: ' +student.points+ '</p>';
    return report;
  }
 while(true){

    search = prompt('type a student name to search the record, and to end type \'quit');
    if (search === null || search.toLowerCase() === 'quit'){
        break;
    }


        for (var i=0; i< students.length ; i+=1){
            student = students[i];
            if ( student.name.toLowerCase() === search.toLowerCase()){   
           message = getStudentRecord(student);
            print(message);
          }

    }
}

2 Answers

Olga DC
Olga DC
16,680 Points

The print function is replacing what's inside the html div each time it is called. That's why you can only see the last student you searched for. I found changing the code inside the print function to this one solved that problem:

function print(message) {
  document.write(message);
}
Matthew Long
Matthew Long
28,407 Points

You may be referring to the change in behavior in browsers since the recording of the video. This is explained in the teachers notes.

Saqib Ishfaq
Saqib Ishfaq
13,912 Points

no! only one student name is printed even when i type quit in the end(as per browser behaviour).if i want to see 2 students names together its doesn't get printed on the page