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PHP Object-Oriented PHP Basics (Retired) Inheritance, Interfaces, and Exceptions Final Challenge

Posted by Andrew Messamore
Andrew Messamore
9,708 Points

OOP PHP. Challenge 6 of 7. Concatenation of method.

For some reason my code is not being accepted. I've tried multiple concatenations and have not gotten anywhere. I'm sure its a grammatical error, but I am tired of looking at it and need fresh eyes.

fish.php 
<?php

class Fish
{
    public $common_name;
    public $flavor;
    public $record_weight;

    function __construct($name, $flavor, $record){
        $this->common_name = $name;
        $this->flavor = $flavor;
        $this->record_weight = $record;
    }
  public function getInfo() {
    return $this->species . " " . $this->common_name . "tastes" . $this->flavor . ". " . "The record" . 
      $this->species . " " . $this->name . " weighed" . $this->record_weight . ".";
  }
//It should be: $this->record_weight . " " . $this->species


}
$brook_trout = new Trout("Trout", "Delicious", "14 pounds 8 ounces", "Brook");

?>

2 Answers

Ted Sumner
PLUS
Ted Sumner
Courses Plus Student 17,967 Points
Ted Sumner
Ted Sumner
Courses Plus Student 17,967 Points

I am not sure where your new class Trout is. This is the entire passing code. There are several ways to compete the concatenation.

<?php

class Fish
{
    public $common_name;
    public $flavor;
    public $record_weight;

    function __construct($name, $flavor, $record){
        $this->common_name = $name;
        $this->flavor = $flavor;
        $this->record_weight = $record;
    }

    public function getInfo() {
        $output  = "The {$this->common_name} is an awesome fish. ";
        $output .= "It is very {$this->flavor} when eaten. ";
        $output .= "Currently the world record {$this->common_name} weighed {$this->record_weight}.";
        return $output;
    }
}

class Trout extends Fish {

  public $species;

  function __construct ($name, $flavor, $record, $species){
    parent::__construct ($name, $flavor, $record);
    $this->species = $species;
  }

  function getInfo() {
    return "$this->species $this->common_name tastes $this->flavor. The record $this->species $this->common_name $this->record_weight.";

  }
}

$brook_trout = new Trout("Trout", "Delicious", "14 pounds 8 ounces", "Brook");
echo $brook_trout->getInfo();
?>
Andrew Messamore
Andrew Messamore
9,708 Points

Thanks Ted.

That worked great.

Andy

Ted Sumner
Ted Sumner
Courses Plus Student 17,967 Points

Please mark best answer when your questions are answered in the Community.

Robbie Thomas
Robbie Thomas
31,093 Points
Robbie Thomas
Robbie Thomas
31,093 Points

This also worked for me too!