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Python Python Basics (2015) Shopping List App Break

Posted by shivani chauhan
shivani chauhan
476 Points

Oops, I forgot that I need to break out of the loop when the current item is the string "STOP". Help me add that code!

sorry but I've still error. please someone fix this

breaks.py 
def loopy(items):
    # Code goes here
    for item in items:
        print(item)
        if item == "STOP":
            break
        else:
            print(item)

1 Answer

Jennifer Nordell
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STAFF
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Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! You're doing great, but you have an extra print statement. During your loop, you print the item then ask if it was equal to "STOP". This means that it will have also printed STOP as well. If it was STOP, it will be the last thing that was printed. However, if it wasn't equal to "STOP" that item will also be printed again.

The solution is to remove the print statement at the very top of the loop. You should only print if the item wasn't equal to "STOP".

Hope this helps! :sparkles:

shivani chauhan
shivani chauhan
476 Points

yeah! thank you #jennifer. actually I Was thinking about it.