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Python Python Basics (2015) Shopping List App Break

Posted by Abubakar Gataev
Abubakar Gataev
2,226 Points

Oops, I forgot that I need to break out of the loop when the current item is the string "STOP". Help me add that code!

please help again i really don't know what i'm doing wrong!

breaks.py 
def loopy(items):
    for b in items:
        print (b)
    if b == "STOP" :
        break

2 Answers

Keir Clyne
Keir Clyne
2,223 Points
Keir Clyne
Keir Clyne
2,223 Points

Think I've found your problem. They want you to stop printing at the "STOP" but without printing "STOP" itself. So you should put the print function after the break function as shown bellow: 

def loopy(items):
    for b in items:
        if b == "STOP":
            break
        print(b)
Keir Clyne
Keir Clyne
2,223 Points
Keir Clyne
Keir Clyne
2,223 Points

When you are writing for loops make sure you are taking notice of the indentation.

So when you write the code it should look like this:

for something in something_else:
    if thing in something_else:
        print(thing)
        break

A good rule of thumb is that normally after you've given an instruction with a colon at the end you go to a new line and then indent.

Hope this helps!

Abubakar Gataev
Abubakar Gataev
2,226 Points

I tried it but it didn't work or I did someothing wrong. I wrote this: def loopy(items): for b in items: if b == "STOP" : print(items)
break