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Python Python Basics (2015) Logic in Python Try and Except

Oops! It loops like Task 1 is no longer passing try except

You're doing great! Just one more task but it's a bigger one. Right now, we turn everything into a float. That's great so long as we're getting numbers or numbers as a string. We should handle cases where we get a non-number, though. Add a try block before where you turn your arguments into floats. Then add an except to catch the possible ValueError. Inside the except block, return None. If you're following the structure from the videos, add an else: for your final return of the added floats.

trial.py
def add(num1 , num2):
  try:
    num3 = int(num1)
    num4 = int(num2)
  except ValueError:
    return None
  else:
    return float(num1) + float(num2)

2 Answers

Michael Hulet
Michael Hulet
47,842 Points

The problem is that you're trying to convert them to ints in your try block. Instead, you should convert them to floats, like this:

def add(num1 , num2):
  try:
    num3 = float(num1)
    num4 = float(num2)
  except ValueError:
    return None
  else:
    # They're already floats, so you don't have to convert them again
    return num1 + num2

Oh

Thanks you

That works :)