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Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today. # operators.swift i dont understand the following sense !

i nee some help to resolve this sense....

operators.swift
```var results: [Int] = []

for n in 1...100 {

}
```

Hi Diogo!

So, in this challenge you have a range from 1 to 100. And in this range you have to find numbers which are both odd and a multiple of 7 Odd numbers are numbers like 1, 3, 5, 7, 9 etc. In other words, it's the opposite of even numbers (2, 4, 6, 8 ..., simply numbers which are a multiple of 2). Multiple of number x is such number that if you divide this number by x, there is nothing left Example: 14/7 = 2 (nothing's left so 14 is a multiple of number 7) 15/7 = 2 (and there's left 1 because 2*7=14 and you need to add 1 to have 15) In code it's like this: x%7==0 ("what's left of this dividing is equal to 0"). And with the odd numbers it's similiar. First, you have to find numbers which are a multiple of 2 and then negate it (!=)

I'm stilling lost unfortunately !! i don't understand what command i need to use for it...

swift_lint.swift:10:4: error: expected expression in != 1 ^

i have this follow problem and i can't know why....

So, I did this challenge and this is what you should write:

```if n%7==0 && !(n%2==0) {
results.append(n)
}
```

Look at the code and if you don't understand me, tell me and I will explain it.

Anyway, it's quite weird that this way it doesn't work:

```if n%7==0 && n%2!=0 {
results.append(n)
}
```

If somebody knows why, I will be more than happy for explanation :)