Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript

Posted by Douglas Watts
Douglas Watts
5,464 Points

Parameter Confusion

Can someone please tell me why the 'greeting' parameter prints out before the 'name' parameter (in the console) from this code:

function sayHello(name ,greeting) {
    if (typeof greeting === 'undefined'){
        greeting = 'Hello' ; 
        } 
    console.log(greeting + " World! " + name);
}

sayHello("Doug", "Greetings");

sayHello("Doug");

2 Answers

tihomirvelev
tihomirvelev
14,109 Points

Hello,

It's just the way the code is written.

In the console.log function, the first parameter for printing is "greeting", then is the string " World! " and the is the "name" parameter. The function prints the things from left to right.

If this line of code was written like that for example: console.log(name + " World! " + greeting);

then the first output will be the "name" parameter, then " World! " and the last thing will be the "greeting" parameter.

Douglas Watts
Douglas Watts
5,464 Points
Douglas Watts
Douglas Watts
5,464 Points

I see, so it's the command that dictates the order...thanks, that's just what i needed!!!